Integrand size = 19, antiderivative size = 218 \[ \int \frac {\left (b x+c x^2\right )^3}{(d+e x)^6} \, dx=\frac {c^3 x}{e^6}-\frac {d^3 (c d-b e)^3}{5 e^7 (d+e x)^5}+\frac {3 d^2 (c d-b e)^2 (2 c d-b e)}{4 e^7 (d+e x)^4}-\frac {d (c d-b e) \left (5 c^2 d^2-5 b c d e+b^2 e^2\right )}{e^7 (d+e x)^3}+\frac {(2 c d-b e) \left (10 c^2 d^2-10 b c d e+b^2 e^2\right )}{2 e^7 (d+e x)^2}-\frac {3 c \left (5 c^2 d^2-5 b c d e+b^2 e^2\right )}{e^7 (d+e x)}-\frac {3 c^2 (2 c d-b e) \log (d+e x)}{e^7} \]
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Time = 0.13 (sec) , antiderivative size = 218, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {712} \[ \int \frac {\left (b x+c x^2\right )^3}{(d+e x)^6} \, dx=-\frac {3 c \left (b^2 e^2-5 b c d e+5 c^2 d^2\right )}{e^7 (d+e x)}+\frac {(2 c d-b e) \left (b^2 e^2-10 b c d e+10 c^2 d^2\right )}{2 e^7 (d+e x)^2}-\frac {d (c d-b e) \left (b^2 e^2-5 b c d e+5 c^2 d^2\right )}{e^7 (d+e x)^3}-\frac {3 c^2 (2 c d-b e) \log (d+e x)}{e^7}-\frac {d^3 (c d-b e)^3}{5 e^7 (d+e x)^5}+\frac {3 d^2 (c d-b e)^2 (2 c d-b e)}{4 e^7 (d+e x)^4}+\frac {c^3 x}{e^6} \]
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Rule 712
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {c^3}{e^6}+\frac {d^3 (c d-b e)^3}{e^6 (d+e x)^6}-\frac {3 d^2 (c d-b e)^2 (2 c d-b e)}{e^6 (d+e x)^5}+\frac {3 d (c d-b e) \left (5 c^2 d^2-5 b c d e+b^2 e^2\right )}{e^6 (d+e x)^4}+\frac {(2 c d-b e) \left (-10 c^2 d^2+10 b c d e-b^2 e^2\right )}{e^6 (d+e x)^3}+\frac {3 c \left (5 c^2 d^2-5 b c d e+b^2 e^2\right )}{e^6 (d+e x)^2}-\frac {3 c^2 (2 c d-b e)}{e^6 (d+e x)}\right ) \, dx \\ & = \frac {c^3 x}{e^6}-\frac {d^3 (c d-b e)^3}{5 e^7 (d+e x)^5}+\frac {3 d^2 (c d-b e)^2 (2 c d-b e)}{4 e^7 (d+e x)^4}-\frac {d (c d-b e) \left (5 c^2 d^2-5 b c d e+b^2 e^2\right )}{e^7 (d+e x)^3}+\frac {(2 c d-b e) \left (10 c^2 d^2-10 b c d e+b^2 e^2\right )}{2 e^7 (d+e x)^2}-\frac {3 c \left (5 c^2 d^2-5 b c d e+b^2 e^2\right )}{e^7 (d+e x)}-\frac {3 c^2 (2 c d-b e) \log (d+e x)}{e^7} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 242, normalized size of antiderivative = 1.11 \[ \int \frac {\left (b x+c x^2\right )^3}{(d+e x)^6} \, dx=-\frac {b^3 e^3 \left (d^3+5 d^2 e x+10 d e^2 x^2+10 e^3 x^3\right )+12 b^2 c e^2 \left (d^4+5 d^3 e x+10 d^2 e^2 x^2+10 d e^3 x^3+5 e^4 x^4\right )-b c^2 d e \left (137 d^4+625 d^3 e x+1100 d^2 e^2 x^2+900 d e^3 x^3+300 e^4 x^4\right )+2 c^3 \left (87 d^6+375 d^5 e x+600 d^4 e^2 x^2+400 d^3 e^3 x^3+50 d^2 e^4 x^4-50 d e^5 x^5-10 e^6 x^6\right )+60 c^2 (2 c d-b e) (d+e x)^5 \log (d+e x)}{20 e^7 (d+e x)^5} \]
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Time = 1.96 (sec) , antiderivative size = 255, normalized size of antiderivative = 1.17
method | result | size |
norman | \(\frac {\frac {c^{3} x^{6}}{e}-\frac {d^{3} \left (b^{3} e^{3}+12 b^{2} d \,e^{2} c -137 b \,c^{2} d^{2} e +274 c^{3} d^{3}\right )}{20 e^{7}}-\frac {\left (3 b^{2} e^{2} c -15 d e b \,c^{2}+30 c^{3} d^{2}\right ) x^{4}}{e^{3}}-\frac {\left (b^{3} e^{3}+12 b^{2} d \,e^{2} c -90 b \,c^{2} d^{2} e +180 c^{3} d^{3}\right ) x^{3}}{2 e^{4}}-\frac {d \left (b^{3} e^{3}+12 b^{2} d \,e^{2} c -110 b \,c^{2} d^{2} e +220 c^{3} d^{3}\right ) x^{2}}{2 e^{5}}-\frac {d^{2} \left (b^{3} e^{3}+12 b^{2} d \,e^{2} c -125 b \,c^{2} d^{2} e +250 c^{3} d^{3}\right ) x}{4 e^{6}}}{\left (e x +d \right )^{5}}+\frac {3 c^{2} \left (b e -2 c d \right ) \ln \left (e x +d \right )}{e^{7}}\) | \(255\) |
risch | \(\frac {c^{3} x}{e^{6}}+\frac {\left (-3 b^{2} c \,e^{5}+15 b \,c^{2} d \,e^{4}-15 c^{3} d^{2} e^{3}\right ) x^{4}-\frac {e^{2} \left (b^{3} e^{3}+12 b^{2} d \,e^{2} c -90 b \,c^{2} d^{2} e +100 c^{3} d^{3}\right ) x^{3}}{2}-\frac {d e \left (b^{3} e^{3}+12 b^{2} d \,e^{2} c -110 b \,c^{2} d^{2} e +130 c^{3} d^{3}\right ) x^{2}}{2}-\frac {d^{2} \left (b^{3} e^{3}+12 b^{2} d \,e^{2} c -125 b \,c^{2} d^{2} e +154 c^{3} d^{3}\right ) x}{4}-\frac {d^{3} \left (b^{3} e^{3}+12 b^{2} d \,e^{2} c -137 b \,c^{2} d^{2} e +174 c^{3} d^{3}\right )}{20 e}}{e^{6} \left (e x +d \right )^{5}}+\frac {3 c^{2} \ln \left (e x +d \right ) b}{e^{6}}-\frac {6 c^{3} d \ln \left (e x +d \right )}{e^{7}}\) | \(260\) |
default | \(\frac {c^{3} x}{e^{6}}-\frac {3 c \left (b^{2} e^{2}-5 b c d e +5 c^{2} d^{2}\right )}{e^{7} \left (e x +d \right )}+\frac {d \left (b^{3} e^{3}-6 b^{2} d \,e^{2} c +10 b \,c^{2} d^{2} e -5 c^{3} d^{3}\right )}{e^{7} \left (e x +d \right )^{3}}-\frac {3 d^{2} \left (b^{3} e^{3}-4 b^{2} d \,e^{2} c +5 b \,c^{2} d^{2} e -2 c^{3} d^{3}\right )}{4 e^{7} \left (e x +d \right )^{4}}+\frac {d^{3} \left (b^{3} e^{3}-3 b^{2} d \,e^{2} c +3 b \,c^{2} d^{2} e -c^{3} d^{3}\right )}{5 e^{7} \left (e x +d \right )^{5}}-\frac {b^{3} e^{3}-12 b^{2} d \,e^{2} c +30 b \,c^{2} d^{2} e -20 c^{3} d^{3}}{2 e^{7} \left (e x +d \right )^{2}}+\frac {3 c^{2} \left (b e -2 c d \right ) \ln \left (e x +d \right )}{e^{7}}\) | \(265\) |
parallelrisch | \(\frac {300 \ln \left (e x +d \right ) x b \,c^{2} d^{4} e^{2}-b^{3} d^{3} e^{3}-60 x^{4} b^{2} c \,e^{6}-600 x^{4} c^{3} d^{2} e^{4}-1800 x^{3} c^{3} d^{3} e^{3}-10 x^{2} b^{3} d \,e^{5}-2200 x^{2} c^{3} d^{4} e^{2}-5 x \,b^{3} d^{2} e^{4}-1250 x \,c^{3} d^{5} e -274 c^{3} d^{6}+600 \ln \left (e x +d \right ) x^{2} b \,c^{2} d^{3} e^{3}+600 \ln \left (e x +d \right ) x^{3} b \,c^{2} d^{2} e^{4}-600 \ln \left (e x +d \right ) x \,c^{3} d^{5} e +20 x^{6} c^{3} e^{6}+300 \ln \left (e x +d \right ) x^{4} b \,c^{2} d \,e^{5}+300 x^{4} b \,c^{2} d \,e^{5}-120 x^{3} b^{2} c d \,e^{5}-1200 \ln \left (e x +d \right ) x^{2} c^{3} d^{4} e^{2}-1200 \ln \left (e x +d \right ) x^{3} c^{3} d^{3} e^{3}-12 b^{2} c \,d^{4} e^{2}+137 b \,c^{2} d^{5} e -600 \ln \left (e x +d \right ) x^{4} c^{3} d^{2} e^{4}+900 x^{3} b \,c^{2} d^{2} e^{4}-120 x^{2} b^{2} c \,d^{2} e^{4}+1100 x^{2} b \,c^{2} d^{3} e^{3}+60 \ln \left (e x +d \right ) b \,c^{2} d^{5} e -60 x \,b^{2} c \,d^{3} e^{3}+60 \ln \left (e x +d \right ) x^{5} b \,c^{2} e^{6}-120 \ln \left (e x +d \right ) x^{5} c^{3} d \,e^{5}-10 x^{3} b^{3} e^{6}-120 \ln \left (e x +d \right ) c^{3} d^{6}+625 x b \,c^{2} d^{4} e^{2}}{20 e^{7} \left (e x +d \right )^{5}}\) | \(484\) |
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Leaf count of result is larger than twice the leaf count of optimal. 462 vs. \(2 (212) = 424\).
Time = 0.26 (sec) , antiderivative size = 462, normalized size of antiderivative = 2.12 \[ \int \frac {\left (b x+c x^2\right )^3}{(d+e x)^6} \, dx=\frac {20 \, c^{3} e^{6} x^{6} + 100 \, c^{3} d e^{5} x^{5} - 174 \, c^{3} d^{6} + 137 \, b c^{2} d^{5} e - 12 \, b^{2} c d^{4} e^{2} - b^{3} d^{3} e^{3} - 20 \, {\left (5 \, c^{3} d^{2} e^{4} - 15 \, b c^{2} d e^{5} + 3 \, b^{2} c e^{6}\right )} x^{4} - 10 \, {\left (80 \, c^{3} d^{3} e^{3} - 90 \, b c^{2} d^{2} e^{4} + 12 \, b^{2} c d e^{5} + b^{3} e^{6}\right )} x^{3} - 10 \, {\left (120 \, c^{3} d^{4} e^{2} - 110 \, b c^{2} d^{3} e^{3} + 12 \, b^{2} c d^{2} e^{4} + b^{3} d e^{5}\right )} x^{2} - 5 \, {\left (150 \, c^{3} d^{5} e - 125 \, b c^{2} d^{4} e^{2} + 12 \, b^{2} c d^{3} e^{3} + b^{3} d^{2} e^{4}\right )} x - 60 \, {\left (2 \, c^{3} d^{6} - b c^{2} d^{5} e + {\left (2 \, c^{3} d e^{5} - b c^{2} e^{6}\right )} x^{5} + 5 \, {\left (2 \, c^{3} d^{2} e^{4} - b c^{2} d e^{5}\right )} x^{4} + 10 \, {\left (2 \, c^{3} d^{3} e^{3} - b c^{2} d^{2} e^{4}\right )} x^{3} + 10 \, {\left (2 \, c^{3} d^{4} e^{2} - b c^{2} d^{3} e^{3}\right )} x^{2} + 5 \, {\left (2 \, c^{3} d^{5} e - b c^{2} d^{4} e^{2}\right )} x\right )} \log \left (e x + d\right )}{20 \, {\left (e^{12} x^{5} + 5 \, d e^{11} x^{4} + 10 \, d^{2} e^{10} x^{3} + 10 \, d^{3} e^{9} x^{2} + 5 \, d^{4} e^{8} x + d^{5} e^{7}\right )}} \]
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Time = 145.84 (sec) , antiderivative size = 326, normalized size of antiderivative = 1.50 \[ \int \frac {\left (b x+c x^2\right )^3}{(d+e x)^6} \, dx=\frac {c^{3} x}{e^{6}} + \frac {3 c^{2} \left (b e - 2 c d\right ) \log {\left (d + e x \right )}}{e^{7}} + \frac {- b^{3} d^{3} e^{3} - 12 b^{2} c d^{4} e^{2} + 137 b c^{2} d^{5} e - 174 c^{3} d^{6} + x^{4} \left (- 60 b^{2} c e^{6} + 300 b c^{2} d e^{5} - 300 c^{3} d^{2} e^{4}\right ) + x^{3} \left (- 10 b^{3} e^{6} - 120 b^{2} c d e^{5} + 900 b c^{2} d^{2} e^{4} - 1000 c^{3} d^{3} e^{3}\right ) + x^{2} \left (- 10 b^{3} d e^{5} - 120 b^{2} c d^{2} e^{4} + 1100 b c^{2} d^{3} e^{3} - 1300 c^{3} d^{4} e^{2}\right ) + x \left (- 5 b^{3} d^{2} e^{4} - 60 b^{2} c d^{3} e^{3} + 625 b c^{2} d^{4} e^{2} - 770 c^{3} d^{5} e\right )}{20 d^{5} e^{7} + 100 d^{4} e^{8} x + 200 d^{3} e^{9} x^{2} + 200 d^{2} e^{10} x^{3} + 100 d e^{11} x^{4} + 20 e^{12} x^{5}} \]
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Time = 0.20 (sec) , antiderivative size = 311, normalized size of antiderivative = 1.43 \[ \int \frac {\left (b x+c x^2\right )^3}{(d+e x)^6} \, dx=-\frac {174 \, c^{3} d^{6} - 137 \, b c^{2} d^{5} e + 12 \, b^{2} c d^{4} e^{2} + b^{3} d^{3} e^{3} + 60 \, {\left (5 \, c^{3} d^{2} e^{4} - 5 \, b c^{2} d e^{5} + b^{2} c e^{6}\right )} x^{4} + 10 \, {\left (100 \, c^{3} d^{3} e^{3} - 90 \, b c^{2} d^{2} e^{4} + 12 \, b^{2} c d e^{5} + b^{3} e^{6}\right )} x^{3} + 10 \, {\left (130 \, c^{3} d^{4} e^{2} - 110 \, b c^{2} d^{3} e^{3} + 12 \, b^{2} c d^{2} e^{4} + b^{3} d e^{5}\right )} x^{2} + 5 \, {\left (154 \, c^{3} d^{5} e - 125 \, b c^{2} d^{4} e^{2} + 12 \, b^{2} c d^{3} e^{3} + b^{3} d^{2} e^{4}\right )} x}{20 \, {\left (e^{12} x^{5} + 5 \, d e^{11} x^{4} + 10 \, d^{2} e^{10} x^{3} + 10 \, d^{3} e^{9} x^{2} + 5 \, d^{4} e^{8} x + d^{5} e^{7}\right )}} + \frac {c^{3} x}{e^{6}} - \frac {3 \, {\left (2 \, c^{3} d - b c^{2} e\right )} \log \left (e x + d\right )}{e^{7}} \]
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Time = 0.26 (sec) , antiderivative size = 265, normalized size of antiderivative = 1.22 \[ \int \frac {\left (b x+c x^2\right )^3}{(d+e x)^6} \, dx=\frac {c^{3} x}{e^{6}} - \frac {3 \, {\left (2 \, c^{3} d - b c^{2} e\right )} \log \left ({\left | e x + d \right |}\right )}{e^{7}} - \frac {174 \, c^{3} d^{6} - 137 \, b c^{2} d^{5} e + 12 \, b^{2} c d^{4} e^{2} + b^{3} d^{3} e^{3} + 60 \, {\left (5 \, c^{3} d^{2} e^{4} - 5 \, b c^{2} d e^{5} + b^{2} c e^{6}\right )} x^{4} + 10 \, {\left (100 \, c^{3} d^{3} e^{3} - 90 \, b c^{2} d^{2} e^{4} + 12 \, b^{2} c d e^{5} + b^{3} e^{6}\right )} x^{3} + 10 \, {\left (130 \, c^{3} d^{4} e^{2} - 110 \, b c^{2} d^{3} e^{3} + 12 \, b^{2} c d^{2} e^{4} + b^{3} d e^{5}\right )} x^{2} + 5 \, {\left (154 \, c^{3} d^{5} e - 125 \, b c^{2} d^{4} e^{2} + 12 \, b^{2} c d^{3} e^{3} + b^{3} d^{2} e^{4}\right )} x}{20 \, {\left (e x + d\right )}^{5} e^{7}} \]
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Time = 9.64 (sec) , antiderivative size = 312, normalized size of antiderivative = 1.43 \[ \int \frac {\left (b x+c x^2\right )^3}{(d+e x)^6} \, dx=\frac {c^3\,x}{e^6}-\frac {x^4\,\left (3\,b^2\,c\,e^5-15\,b\,c^2\,d\,e^4+15\,c^3\,d^2\,e^3\right )+x^2\,\left (\frac {b^3\,d\,e^4}{2}+6\,b^2\,c\,d^2\,e^3-55\,b\,c^2\,d^3\,e^2+65\,c^3\,d^4\,e\right )+x\,\left (\frac {b^3\,d^2\,e^3}{4}+3\,b^2\,c\,d^3\,e^2-\frac {125\,b\,c^2\,d^4\,e}{4}+\frac {77\,c^3\,d^5}{2}\right )+\frac {b^3\,d^3\,e^3+12\,b^2\,c\,d^4\,e^2-137\,b\,c^2\,d^5\,e+174\,c^3\,d^6}{20\,e}+x^3\,\left (\frac {b^3\,e^5}{2}+6\,b^2\,c\,d\,e^4-45\,b\,c^2\,d^2\,e^3+50\,c^3\,d^3\,e^2\right )}{d^5\,e^6+5\,d^4\,e^7\,x+10\,d^3\,e^8\,x^2+10\,d^2\,e^9\,x^3+5\,d\,e^{10}\,x^4+e^{11}\,x^5}-\frac {\ln \left (d+e\,x\right )\,\left (6\,c^3\,d-3\,b\,c^2\,e\right )}{e^7} \]
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